GeezerVison

The error function is an entire function; it has no singularities (except at infinity) and its Taylor expansion always converges. For $x\gg 1$, however, cancellation of leading terms makes the Taylor expansion impractical.

The defining integral cannot be evaluated in closed form in terms of elementary functions (see Liouville's theorem), but by expanding the integrand $e^{-z^2}$ into its Maclaurin series, integrating term by term,^[5] and using the fact that $\mathrm{erf}\left(0\right)=0$, one obtains the error function's Maclaurin series as: $\begin{array}{cc}\mathrm{erf}\left(z\right)& =\frac{2}{\sqrt{\pi }}\sum _{n=0}^{\infty }\frac{(-1{)}^n{z}^{2n+1}}{n!(2n+1)}\\ & =\frac{2}{\sqrt{\pi }}(z-\frac{z^3}{3}+\frac{z^5}{10}-\frac{z^7}{42}+\frac{z^9}{216}-\cdots )\end{array}$ which holds for every complex number $z$. The denominator terms form sequence A007680 in the OEIS. This is a special case of Kummer's confluent hypergeometric function:

$\mathrm{erf}\left(z\right)=\frac{2z}{\sqrt{\pi }}{}_1{F}_1(\frac{1}{2},\frac{3}{2},-z^2).$

For iterative calculation of the above series, the following alternative formulation may be useful: $\begin{array}{cc}\mathrm{erf}\left(z\right)& =\frac{2}{\sqrt{\pi }}\sum _{n=0}^{\infty }\left(z\prod _{k=1}^n\frac{-(2k-1)z^2}{k(2k+1)}\right)\\ & =\frac{2}{\sqrt{\pi }}\sum _{n=0}^{\infty }\frac{z}{2n+1}\prod _{k=1}^n\frac{-z^2}{k},\end{array}$ because

$\frac{-(2k-1)z^2}{k(2k+1)}$

expresses the multiplier to turn the $k$-th term into the $(k+1)$-th term (considering $z$ as the first term).

The imaginary error function has a similar Maclaurin series: $\begin{array}{cc}\mathrm{erfi}\left(z\right)& =\frac{2}{\sqrt{\pi }}\sum _{n=0}^{\infty }\frac{z^{2n+1}}{n!(2n+1)}\\ & =\frac{2}{\sqrt{\pi }}(z+\frac{z^3}{3}+\frac{z^5}{10}+\frac{z^7}{42}+\frac{z^9}{216}+\cdots )\end{array}$ which holds for every complex number $z$.

The derivative of the error function follows immediately from its definition: $\frac{d}{dz}\mathrm{erf}\left(z\right)=\frac{2}{\sqrt{\pi }}{e}^{-z^2}.$ From this, the derivative of the imaginary error function is also immediate: $\frac{d}{dz}\mathrm{erfi}\left(z\right)=\frac{2}{\sqrt{\pi }}{e}^{z^2}.$Higher order derivatives are given by ${\mathrm{erf}}^{\left(k\right)}\left(z\right)=\frac{2(-1{)}^{k-1}}{\sqrt{\pi }}{𝐻}_{k-1}\left(z\right)e^{-z^2}=\frac{2}{\sqrt{\pi }}\frac{d^{k-1}}{d{z}^{k-1}}\left(e^{-z^2}\right),$ where the $H_k$ are the physicists' Hermite polynomials.^[6]

An antiderivative of the error function, obtainable by integration by parts, is $\int \mathrm{erf}\left(z\right)dz=z\mathrm{erf}\left(z\right)+\frac{e^{-z^2}}{\sqrt{\pi }}+C.$ An antiderivative of the imaginary error function, also obtainable by integration by parts, is $\int \mathrm{erfi}\left(z\right)dz=z\mathrm{erfi}\left(z\right)-\frac{e^{z^2}}{\sqrt{\pi }}+C.$

An expansion which converges more rapidly for all real values of $x$ than a Taylor expansion^[7] is obtained by using Bürmann's theorem:^[8] $\begin{array}{cc}\mathrm{erf}\left(x\right)& =\frac{2}{\sqrt{\pi }}\mathrm{sgn}\left(x\right)\cdot \sqrt{1-e^{-x^2}}(1-\frac{1}{12}(1-e^{-x^2})-\frac{7}{480}{(1-e^{-x^2})}^2-\frac{5}{896}{(1-e^{-x^2})}^3-\cdots )\\ & =\frac{2}{\sqrt{\pi }}\mathrm{sgn}\left(x\right)\cdot \sqrt{1-e^{-x^2}}(\frac{\sqrt{\pi }}{2}+\sum _{k=1}^{\infty }{c}_k{e}^{-k{x}^2})\end{array}$ where $\mathrm{sgn}$ is the sign function. By keeping only the first two coefficients and choosing $c_1=31/200$ and $c_2=-341/8000$, the resulting approximation shows its largest relative error at $x=\pm 1.40587$, where it is less than $0.0034361$: $\mathrm{erf}\left(x\right)\approx \frac{2}{\sqrt{\pi }}\mathrm{sgn}\left(x\right)\cdot \sqrt{1-e^{-x^2}}(\frac{\sqrt{\pi }}{2}+\frac{31}{200}{e}^{-x^2}-\frac{341}{8000}{e}^{-2x^2}).$

Given a complex number $z$, there is not a unique complex number $w$ satisfying $\mathrm{erf}\left(w\right)=z$, so a true inverse function would be multivalued. However, for $-1<x<1$, there is a unique real number denoted ${\mathrm{erf}}^{-1}\left(x\right)$ satisfying

$\mathrm{erf}\left({\mathrm{erf}}^{-1}\right(x\left)\right)=x.$

The inverse error function is usually defined with domain $(-1,1)$, and it is restricted to this domain in many computer algebra systems. However, it can be extended to the disk $\left|z\right|<1$ of the complex plane, using the Maclaurin series^[9]

${\mathrm{erf}}^{-1}\left(z\right)=\sum _{k=0}^{\infty }\frac{c_k}{2k+1}{\left(\frac{\sqrt{\pi }}{2}z\right)}^{2k+1},$

where $c_0=1$ and $\begin{array}{cc}{c}_k& =\sum _{m=0}^{k-1}\frac{c_m{c}_{k-1-m}}{(m+1)(2m+1)}\\ & =\{1,1,\frac{7}{6},\frac{127}{90},\frac{4369}{2520},\frac{34807}{16200},\dots \}.\end{array}$

So we have the series expansion (common factors have been canceled from numerators and denominators):

${\mathrm{erf}}^{-1}\left(z\right)=\frac{\sqrt{\pi }}{2}(z+\frac{\pi }{12}{z}^3+\frac{7{\pi }^2}{480}{z}^5+\frac{127{\pi }^3}{40320}{z}^7+\frac{4369{\pi }^4}{5806080}{z}^9+\frac{34807{\pi }^5}{182476800}{z}^{11}+\cdots ).$

After cancellation the numerator and denominator are values in (sequence A092676 in the OEIS) and (sequence A092677 in the OEIS) respectively; without cancellation the numerator terms are values in (sequence A002067 in the OEIS). The error function's value at $\pm \infty$ is equal to $\pm 1$.

For $\left|z\right|<1$, we have $\mathrm{erf}\left({\mathrm{erf}}^{-1}\right(z\left)\right)=z$.

The inverse complementary error function is defined as ${\mathrm{erfc}}^{-1}(1-z)={\mathrm{erf}}^{-1}\left(z\right).$ For real $x$, there is a unique real number ${\mathrm{erfi}}^{-1}\left(x\right)$ satisfying $\mathrm{erfi}\left({\mathrm{erfi}}^{-1}\right(x\left)\right)=x$. The inverse imaginary error function is defined as ${\mathrm{erfi}}^{-1}\left(x\right)$.^[10]

For any real $x$, Newton's method can be used to compute ${\mathrm{erfi}}^{-1}\left(x\right)$, and for $-1\le x\le 1$, the following Maclaurin series converges:

${\mathrm{erfi}}^{-1}\left(z\right)=\sum _{k=0}^{\infty }\frac{(-1{)}^k{c}_k}{2k+1}{\left(\frac{\sqrt{\pi }}{2}z\right)}^{2k+1},$

where $c_k$ is defined as above.

A useful asymptotic expansion of the complementary error function (and therefore also of the error function) for large real $x$ is $\begin{array}{cc}\mathrm{erfc}\left(x\right)& =\frac{e^{-x^2}}{x\sqrt{\pi }}(1+\sum _{n=1}^{\infty }(-1{)}^n\frac{1\cdot 3\cdot 5\cdots (2n-1)}{{\left(2x^2\right)}^n})\\ & =\frac{e^{-x^2}}{x\sqrt{\pi }}\sum _{n=0}^{\infty }(-1{)}^n\frac{(2n-1)!!}{{\left(2x^2\right)}^n},\end{array}$ where $(2n-1)!!$ is the double factorial of $2n-1$, i.e. the product of all odd numbers up to $2n-1$. This series diverges for every finite $x$, and its meaning as asymptotic expansion is that for any integer $N\ge 1$ one has

$\mathrm{erfc}\left(x\right)=\frac{e^{-x^2}}{x\sqrt{\pi }}\sum _{n=0}^{N-1}(-1{)}^n\frac{(2n-1)!!}{{\left(2x^2\right)}^n}+R_N(x),$

where the remainder is

$R_N\left(x\right):=\frac{(-1{)}^N(2N-1)!!}{\sqrt{\pi }\cdot 2^{N-1}}{\int }_x^{\infty }{t}^{-2N}{e}^{-t^2}dt,$

which follows easily by induction, writing

$e^{-t^2}=-\frac{1}{2t}\frac{d}{dt}{e}^{-t^2}$

and integrating by parts. The asymptotic behavior of the remainder term is

$R_N\left(x\right)=O\left(x^{-(1+2N)}{e}^{-x^2}\right)$

as $x\to \infty$. This can be found by

$R_N\left(x\right)\propto {\int }_x^{\infty }{t}^{-2N}{e}^{-t^2}dt=e^{-x^2}{\int }_0^{\infty }(t+x{)}^{-2N}{e}^{-t^2-2tx}dt\le e^{-x^2}{\int }_0^{\infty }{x}^{-2N}{e}^{-2tx}dt\propto x^{-(1+2N)}{e}^{-x^2}.$

For large enough values of $x$, only the first few terms of this asymptotic expansion are needed to obtain a good approximation of $\mathrm{erfc}\left(x\right)$ (while for not too large values of $x$, the above Taylor expansion at 0 provides a very fast convergence).

A continued fraction expansion of the complementary error function was found by Laplace:^[11][12] $\mathrm{erfc}\left(z\right)=\frac{z}{\sqrt{\pi }}{e}^{-z^2}\frac{1}{z^2+\frac{a_1}{1+\frac{a_2}{z^2+\frac{a_3}{1+\cdots }}}}$ where $a_m=\frac{m}{2}$.

The inverse factorial series

$\begin{array}{cc}\mathrm{erfc}\left(z\right)& =\frac{e^{-z^2}}{\sqrt{\pi }z}\sum _{n=0}^{\infty }\frac{{(-1)}^n{Q}_n}{{(z^2+1)}^{\left(n\right)}}\\ & =\frac{e^{-z^2}}{\sqrt{\pi }z}[1-\frac{1}{2}\frac{1}{(z^2+1)}+\frac{1}{4}\frac{1}{(z^2+1)(z^2+2)}-\cdots ]\end{array}$

converges for $\mathrm{Re}\left(z^2\right)>0$. Here

$\begin{array}{cc}{Q}_n& =\frac{1}{\sqrt{\pi }}{\int }_0^{\infty }\tau (\tau -1)\cdots (\tau -n+1){\tau }^{-\frac{1}{2}}{e}^{-\tau }d\tau \\ & =\sum _{k=0}^{n}s(n,k){\left(\frac{1}{2}\right)}^{\left(k\right)}=\sum _{k=0}^{n}s(n,k)\frac{(2k-1)!!}{2^k}\end{array}$

where $z^{\left(n\right)}$ denotes the rising factorial, and $s(n,k)$ denotes a signed Stirling number of the first kind.^[13][14] The Taylor series can be written in terms of the double factorial:

$\mathrm{erf}\left(z\right)=\frac{2}{\sqrt{\pi }}\sum _{n=0}^{\infty }\frac{(-2{)}^n(2n-1)!!}{(2n+1)!}{z}^{2n+1}.$

Abramowitz and Stegun give several approximations of varying accuracy (equations 7.1.25–28) from C. Hastings, Jr.^[15]. This allows one to choose the fastest approximation suitable for a given application. In order of increasing accuracy, they are: $\mathrm{erf}\left(x\right)\approx 1-\frac{1}{{(1+a_{1}x+a_2{x}^2+a_3{x}^3+a_4{x}^4)}^4},x\ge 0$ (maximum error: 5×10⁻⁴)

where a₁ = 0.278393, a₂ = 0.230389, a₃ = 0.000972, a₄ = 0.078108

$\mathrm{erf}\left(x\right)\approx 1-(a_{1}t+a_2{t}^2+a_3{t}^3)e^{-x^2},t=\frac{1}{1+px},x\ge 0$ (maximum error: 2.5×10⁻⁵)

where p = 0.47047, a₁ = 0.3480242, a₂ = −0.0958798, a₃ = 0.7478556

$\mathrm{erf}\left(x\right)\approx 1-\frac{1}{{(1+a_{1}x+a_2{x}^2+\cdots +a_6{x}^6)}^{16}},x\ge 0$ (maximum error: 3×10⁻⁷)

where a₁ = 0.0705230784, a₂ = 0.0422820123, a₃ = 0.0092705272, a₄ = 0.0001520143, a₅ = 0.0002765672, a₆ = 0.0000430638

$\mathrm{erf}\left(x\right)\approx 1-(a_{1}t+a_2{t}^2+\cdots +a_5{t}^5)e^{-x^2},t=\frac{1}{1+px}$ (maximum error: 1.5×10⁻⁷)

where p = 0.3275911, a₁ = 0.254829592, a₂ = −0.284496736, a₃ = 1.421413741, a₄ = −1.453152027, a₅ = 1.061405429

One can improve the accuracy of the Hastings approximation by extending it with three extra parameters, $\mathrm{erf}\left(x\right)\approx 1-(a_{1}t+a_2{t}^2+\cdots +a_5{t}^5+a_6{t}^6+a_7{t}^7)e^{-x^2},t=\frac{1}{1+p_{1}x+p_2{x}^2}$ where p1 = 0.406742016006509, p2 = 0.0072279182302319, a1 = 0.316879890481381, a2 = -0.138329314150635, a3 = 1.08680830347054, a4 = -1.11694155120396, a5 = 1.20644903073232, a6 = -0.393127715207728, a7 = 0.0382613542530727. The maximum error of this approximation is about 2×10⁻⁹. The parameters are obtained by fitting the extended approximation to the accurate values of the error function using the following Python code.

import numpy as np
from math import erf, exp, sqrt
from scipy.optimize import least_squares

#
# Extended A&S approximation:
# erf(x) ≈ 1 − t * exp(−x^2) * (a1 + a2*t + a3*t^2 + ... + a7*t^6)
# where now
#      t = 1 / (1 + p1*x + p2*x^2)
# We fit parameters p1, p2, a1..a7 over x in [0, 10].
#


def approx_erf(params, x):
    p1 = params[0]
    p2 = params[1]
    a = params[2:]

    t = 1.0 / (1.0 + p1 * x + p2 * x * x)

    poly = np.zeros_like(x)
    tt = np.ones_like(x)  # t^0

    # polynomial: a1*t^0 + a2*t^1 + ... + a7*t^6
    for ak in a:
        poly += ak * tt
        tt *= t

    return 1.0 - t * np.exp(-x * x) * poly


def residuals(params, xs, ys):
    return approx_erf(params, xs) - ys


#
# Prepare data for fitting
#

N = 300
xmin = 0
xmax = 10
xs = np.linspace(xmin, xmax, N)
ys = np.array([erf(x) for x in xs], dtype=float)

#
# Initial guess for parameters
# Start from original A&S values and extend them conservatively
#

p1_0 = 0.3275911  # original A&S p
p2_0 = 0.0  # new denominator parameter

# original A&S 5 coefficients, add two => 7 in total
a0 = [
    0.254829592,
    -0.284496736,
    1.421413741,
    -1.453152027,
    1.061405429,
    0.0,  # new term
    0.0,  # another new term
]

params0 = np.array([p1_0, p2_0] + a0, dtype=float)

#
# Fit using nonlinear least squares (Levenberg–Marquardt)
#

result = least_squares(
    residuals, params0, args=(xs, ys), xtol=1e-14, ftol=1e-14, gtol=1e-14, max_nfev=5000
)

params = result.x
p1_fit = params[0]
p2_fit = params[1]
a_fit = params[2:]

#
# Print fitted parameters
#

print("\nFitted parameters:")
print(f"p1 = {p1_fit:.15g},")
print(f"p2 = {p2_fit:.15g},")
for i, ai in enumerate(a_fit, 1):
    print(f"a{i} = {ai:.15g},")

#
# Evaluate approximation error
#

approx_vals = approx_erf(params, xs)
abs_err = np.abs(approx_vals - ys)

print(f"\nMaximum absolute error on [{xmin},{xmax}]:", np.max(abs_err))
print("RMS error:", np.sqrt(np.mean(abs_err**2)))
print("Done.")

All of these approximations are valid for x ≥ 0. To use these approximations for negative x, use the fact that erf(x) is an odd function, so erf(x) = −erf(−x).

Exponential bounds and a pure exponential approximation for the complementary error function are given by^[16] $\begin{array}{cccc}\mathrm{erfc}\left(x\right)& \le \frac{1}{2}{e}^{-2x^2}+\frac{1}{2}{e}^{-x^2}\le e^{-x^2},& & x>0\\ \mathrm{erfc}\left(x\right)& \approx \frac{1}{6}{e}^{-x^2}+\frac{1}{2}{e}^{-\frac{4}{3}{x}^2},& & x>0.\end{array}$

The above have been generalized to sums of N exponentials^[17] with increasing accuracy in terms of N so that erfc(x) can be accurately approximated or bounded by 2Q̃(√2x), where $\tilde{Q}\left(x\right)=\sum _{n=1}^N{a}_n{e}^{-b_n{x}^2}.$ In particular, there is a systematic methodology to solve the numerical coefficients {(a_n,b_n)}^N
_{n = 1} that yield a minimax approximation or bound for the closely related Q-function: Q(x) ≈ Q̃(x), Q(x) ≤ Q̃(x), or Q(x) ≥ Q̃(x) for x ≥ 0. The coefficients {(a_n,b_n)}^N
_{n = 1} for many variations of the exponential approximations and bounds up to N = 25 have been released to open access as a comprehensive dataset.^[18]

A tight approximation of the complementary error function for x ∈ [0,∞) is given by Karagiannidis & Lioumpas (2007),^[19] who showed for the appropriate choice of parameters {A,B} that $\mathrm{erfc}\left(x\right)\approx \frac{(1-e^{-Ax})e^{-x^2}}{B\sqrt{\pi }x}.$ They determined {A,B} = {1.98,1.135}, which gave a good approximation for all x ≥ 0. Alternative coefficients are also available for tailoring accuracy for a specific application or transforming the expression into a tight bound.^[20]

A single-term lower bound is^[21] $\mathrm{erfc}\left(x\right)\ge \sqrt{\frac{2e}{\pi }}\frac{\sqrt{\beta -1}}{\beta }{e}^{-\beta x^2},x\ge 0,\beta >1,$ where the parameter β can be picked to minimize error on the desired interval of approximation.

Another approximation is given by Sergei Winitzki using his "global Padé approximations":^{[22][23]: 2–3} $\mathrm{erf}\left(x\right)\approx \mathrm{sgn}x\cdot \sqrt{1-\exp (-x^2\frac{\frac{4}{\pi }+a{x}^2}{1+a{x}^2})}$ where $a=\frac{8(\pi -3)}{3\pi (4-\pi )}\approx \mathrm{0.140012.}$ This is designed to be very accurate in the neighborhoods of 0 and infinity, and the relative error is less than 0.00035 for all real x. Using the alternate value a ≈ 0.147 reduces the maximum relative error to about 0.00013.^[24]

The extended "global Pade" approximation, $\mathrm{erf}\left(x\right)\approx \mathrm{sgn}x\cdot \sqrt{1-\exp (-x^2\frac{4+0.880877880079853x^2+0.144026670907584x^4+0.0077581300270021x^6}{\pi +0.786235558186528x^2+0.128368576906837x^4+0.00773380006014367x^6})},$ provides a maximum error of about 2×10⁻⁹, as demonstrated by the following Python script.

import numpy,math
from scipy.optimize import least_squares

# approximation to erf(x)

def approx_erf(p,x):
	frac=(4+p[0]*x**2+p[1]*x**4+p[2]*x**6)/(
		math.pi+p[3]*x**2+p[4]*x**4+p[5]*x**6)
	return numpy.sign(x)*numpy.sqrt(
		1-numpy.exp(-x*x*frac))

def residuals(params, xs, ys):
    return approx_erf(params, xs) - ys

# data for fitting

N = 200
xmin = 0
xmax = 9
xs = numpy.linspace(xmin, xmax, N)
ys = numpy.array([math.erf(x) for x in xs], dtype=float)
params0 = numpy.array([0.9,0.1,0.008,0.8,0.1,0.008], dtype=float)

# fitting

result = least_squares(
    residuals, params0, args=(xs, ys),
	xtol=1e-14, ftol=1e-14, gtol=1e-14, max_nfev=5000
)
params = result.x

# print out fitted parameters

print("\nFitted parameters:")
for i, pi in enumerate(params, 0):
    print(f"p{i} = {pi:.15g},")

# evaluate approximation error

approx_vals = approx_erf(params, xs)
abs_err = numpy.abs(approx_vals - ys)

print(f"\nMaximum absolute error on [{xmin},{xmax}]:", numpy.max(abs_err))
print("RMS error:", numpy.sqrt(numpy.mean(abs_err**2)))
print("Done.")

Winitzki's approximation can be inverted to obtain an approximation for the inverse error function: ${\mathrm{erf}}^{-1}\left(x\right)\approx \mathrm{sgn}x\cdot \sqrt{\sqrt{{(\frac{2}{\pi a}+\frac{\ln (1-x^2)}{2})}^2-\frac{\ln (1-x^2)}{a}}-(\frac{2}{\pi a}+\frac{\ln (1-x^2)}{2})}.$

An approximation with a maximal error of 1.2×10⁻⁷ for any real argument is:^[25] $\begin{array}{cc}\mathrm{erf}\left(x\right)& =\{\begin{array}{cc}1-\tau ,& x\ge 0\\ \tau -1,& x<0\end{array}\\ \tau & =t\cdot \exp (-x^2-1.26551223+1.00002368t+0.37409196t^2+0.09678418t^3-0.18628806t^4\\ & +0.27886807t^5-1.13520398t^6+1.48851587t^7-0.82215223t^8+0.17087277t^9)\\ t& =\frac{1}{1+\frac{1}{2}\left|x\right|}\end{array}$

An approximation of $\mathrm{erfc}$ with a maximum relative error less than $2^{-53}$ $(\approx 1.1\times 10^{-16})$ in absolute value is:^[26] for $x\ge 0$, $\begin{array}{cc}\mathrm{erfc}\left(x\right)& =\left(\frac{0.56418958354775629}{x+2.06955023132914151}\right)\left(\frac{x^2+2.71078540045147805x+5.80755613130301624}{x^2+3.47954057099518960x+12.06166887286239555}\right)\\ & \left(\frac{x^2+3.47469513777439592x+12.07402036406381411}{x^2+3.72068443960225092x+8.44319781003968454}\right)\left(\frac{x^2+4.00561509202259545x+9.30596659485887898}{x^2+3.90225704029924078x+6.36161630953880464}\right)\\ & \left(\frac{x^2+5.16722705817812584x+9.12661617673673262}{x^2+4.03296893109262491x+5.13578530585681539}\right)\left(\frac{x^2+5.95908795446633271x+9.19435612886969243}{x^2+4.11240942957450885x+4.48640329523408675}\right)e^{-x^2}\end{array}$ and for $x<0$ $\mathrm{erfc}\left(x\right)=2-\mathrm{erfc}(-x)$

A simple approximation for real-valued arguments can be done through hyperbolic functions: $\mathrm{erf}\left(x\right)\approx z\left(x\right)=\tanh \left(\frac{2}{\sqrt{\pi }}(x+\frac{11}{123}{x}^3)\right)$ which keeps the absolute difference $|\mathrm{erf}\left(x\right)-z(x\left)\right|<0.000358,\forall x$.

Since the error function and the Gaussian Q-function are closely related through the identity $\mathrm{erfc}\left(x\right)=2Q\left(\sqrt{2}x\right)$ or equivalently $Q\left(x\right)=\frac{1}{2}\mathrm{erfc}\left(\frac{x}{\sqrt{2}}\right)$, bounds developed for the Q-function can be adapted to approximate the complementary error function. A pair of tight lower and upper bounds on the Gaussian Q-function for positive arguments $x\in [0,\infty )$ was introduced by Abreu (2012)^[27] based on a simple algebraic expression with only two exponential terms: $\begin{array}{cc}x& \ge 0\\ \frac{1}{2}\mathrm{erfc}\left(\frac{x}{\sqrt{2}}\right)& \ge \frac{1}{12}{e}^{-x^2}+\frac{1}{\sqrt{2\pi }(x+1)}{e}^{-x^2/2}\\ & \le \frac{1}{50}{e}^{-x^2}+\frac{1}{2(x+1)}{e}^{-x^2/2}\\ \frac{1}{25}{e}^{-2x^2}+\frac{1}{x+1}{e}^{-x^2}\ge \mathrm{erfc}\left(x\right)& \ge \frac{1}{6}{e}^{-2x^2}+\frac{1}{2\sqrt{2\pi }(x+1)}{e}^{-x^2}\end{array}$

These bounds stem from a unified form $Q_B(x;a,b)=\frac{\exp (-x^2)}{a}+\frac{\exp (-x^2/2)}{b(x+1)},$ where the parameters $a$ and $b$ are selected to ensure the bounding properties: for the lower bound, $a_L=12$ and $b_L=\sqrt{2\pi }$, and for the upper bound, $a_U=50$ and $b_U=2$. These expressions maintain simplicity and tightness, providing a practical trade-off between accuracy and ease of computation. They are particularly valuable in theoretical contexts, such as communication theory over fading channels, where both functions frequently appear. Additionally, the original Q-function bounds can be extended to $Q^n\left(x\right)$ for positive integers $n$ via the binomial theorem, suggesting potential adaptability for powers of $\mathrm{erfc}\left(x\right)$, though this is less commonly required in error function applications.

The complementary error function, denoted erfc, is defined as $\begin{array}{cc}\mathrm{erfc}\left(x\right)& =1-\mathrm{erf}\left(x\right)\\ & =\frac{2}{\sqrt{\pi }}{\int }_x^{\infty }{e}^{-t^2}dt\\ & =e^{-x^2}\mathrm{erfcx}\left(x\right),\end{array}$ which also defines erfcx, the scaled complementary error function^[28] (which can be used instead of erfc to avoid arithmetic underflow^[28][29]). Another form of erfc x for x ≥ 0 is known as Craig's formula, after its discoverer:^[30] $\mathrm{erfc}(x\mid x\ge 0)=\frac{2}{\pi }{\int }_0^{\frac{\pi }{2}}\exp (-\frac{x^2}{{\sin }^2\theta })d\theta .$ This expression is valid only for positive values of x, but can be used in conjunction with erfc(x) = 2 − erfc(−x) to obtain erfc(x) for negative values. This form is advantageous in that the range of integration is fixed and finite. An extension of this expression for the erfc of the sum of two non-negative variables is^[31] $\mathrm{erfc}(x+y\mid x,y\ge 0)=\frac{2}{\pi }{\int }_0^{\frac{\pi }{2}}\exp (-\frac{x^2}{{\sin }^2\theta }-\frac{y^2}{{\cos }^2\theta })d\theta .$

The imaginary error function, denoted erfi, is defined as $\begin{array}{cc}\mathrm{erfi}\left(x\right)& =-i\mathrm{erf}\left(ix\right)\\ & =\frac{2}{\sqrt{\pi }}{\int }_0^x{e}^{t^2}dt\\ & =\frac{2}{\sqrt{\pi }}{e}^{x^2}D\left(x\right),\end{array}$ where D(x) is the Dawson function (which can be used instead of erfi to avoid arithmetic overflow^[28]).

Despite the name "imaginary error function", erfi(x) is real when x is real.

When the error function is evaluated for arbitrary complex arguments z, the resulting complex error function is usually discussed in scaled form as the Faddeeva function: $w\left(z\right)=e^{-z^2}\mathrm{erfc}(-iz)=\mathrm{erfcx}(-iz).$

The error function is essentially identical to the standard normal cumulative distribution function, denoted Φ, also named norm(x) by some software languages, as they differ only by scaling and translation. Indeed, $\begin{array}{cc}\Phi \left(x\right)& =\frac{1}{\sqrt{2\pi }}{\int }_{-\infty }^x{e}^{\frac{-t^2}{2}}dt\\ & =\frac{1}{2}(1+\mathrm{erf}\left(\frac{x}{\sqrt{2}}\right))\\ & =\frac{1}{2}\mathrm{erfc}(-\frac{x}{\sqrt{2}})\end{array}$ or rearranged for erf and erfc: $\begin{array}{cc}\mathrm{erf}\left(x\right)& =2\Phi \left(x\sqrt{2}\right)-1\\ \mathrm{erfc}\left(x\right)& =2\Phi (-x\sqrt{2})\\ & =2(1-\Phi \left(x\sqrt{2}\right)).\end{array}$

Consequently, the error function is also closely related to the Q-function, which is the tail probability of the standard normal distribution. The Q-function can be expressed in terms of the error function as $\begin{array}{cc}Q\left(x\right)& =\frac{1}{2}-\frac{1}{2}\mathrm{erf}\left(\frac{x}{\sqrt{2}}\right)\\ & =\frac{1}{2}\mathrm{erfc}\left(\frac{x}{\sqrt{2}}\right).\end{array}$

The inverse of Φ is known as the normal quantile function, or probit function and may be expressed in terms of the inverse error function as $\mathrm{probit}\left(p\right)={\Phi }^{-1}\left(p\right)=\sqrt{2}{\mathrm{erf}}^{-1}(2p-1)=-\sqrt{2}{\mathrm{erfc}}^{-1}\left(2p\right).$

The standard normal cdf is used more often in probability and statistics, and the error function is used more often in other branches of mathematics.

The error function is a special case of the Mittag-Leffler function, and can also be expressed as a confluent hypergeometric function (Kummer's function): $\mathrm{erf}\left(x\right)=\frac{2x}{\sqrt{\pi }}M(\frac{1}{2},\frac{3}{2},-x^2).$

It has a simple expression in terms of the Fresnel integral.

In terms of the regularized gamma function P and the incomplete gamma function, $\mathrm{erf}\left(x\right)=\mathrm{sgn}\left(x\right)\cdot P(\frac{1}{2},x^2)=\frac{\mathrm{sgn}\left(x\right)}{\sqrt{\pi }}\gamma (\frac{1}{2},x^2).$sgn(x) is the sign function.

The iterated integrals of the complementary error function are defined by^[32] $\begin{array}{cc}{i}^n\mathrm{erfc}\left(z\right)& ={\int }_z^{\infty }{i}^{n-1}\mathrm{erfc}\left(\zeta \right)d\zeta \\ i^0\mathrm{erfc}\left(z\right)& =\mathrm{erfc}\left(z\right)\\ i^1\mathrm{erfc}\left(z\right)& =\mathrm{ierfc}\left(z\right)=\frac{1}{\sqrt{\pi }}{e}^{-z^2}-z\mathrm{erfc}\left(z\right)\\ i^2\mathrm{erfc}\left(z\right)& =\frac{1}{4}(\mathrm{erfc}(z)-2z\mathrm{ierfc}(z\left)\right)\end{array}$