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GeezerVison is showing github.com — pythonlib/cardinal_pythonlib/stringfunc.py at master · RudolfCardinal/pythonlib Expand file tree/ Copy pathstringfunc.pyMore file actions 156 lines (116 loc) · 4.91 KB / Copy pathstringfunc.pyFile metadata and controls156 lines (116 loc) · 4.91 KB 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 #!/usr/bin/env python # cardinal_pythonlib/sqlalchemy/subproc.py """ =============================================================================== Original code copyright (C) 2009-2022 Rudolf Cardinal ([email protected]). This file is part of cardinal_pythonlib. Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at https://www.apache.org/licenses/LICENSE-2.0 Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License. =============================================================================== """ import re from typing import Any, Dict, Iterable, List import unicodedata # ============================================================================= # Finding # ============================================================================= def find_nth(s: str, x: str, n: int = 0, overlap: bool = False) -> int: r""" Finds the position of *n*\ th occurrence of ``x`` in ``s``, or ``-1`` if there isn't one. - The ``n`` parameter is zero-based (i.e. 0 for the first, 1 for the second...). - If ``overlap`` is true, allows fragments to overlap. If not, they must be distinct. As per https://stackoverflow.com/questions/1883980/find-the-nth-occurrence-of-substring-in-a-string """ length_of_fragment = 1 if overlap else len(x) i = -length_of_fragment for _ in range(n + 1): i = s.find(x, i + length_of_fragment) if i < 0: break return i # ============================================================================= # Splitting # ============================================================================= def split_string(x: str, n: int) -> List[str]: """ Split string into chunks of length n """ # https://stackoverflow.com/questions/9475241/split-string-every-nth-character # noqa: E501 return [x[i : i + n] for i in range(0, len(x), n)] # ============================================================================= # Replacement # ============================================================================= def multiple_replace(text: str, rep: Dict[str, str]) -> str: """ Returns a version of ``text`` in which the keys of ``rep`` (a dict) have been replaced by their values. As per https://stackoverflow.com/questions/6116978/python-replace-multiple-strings. """ rep = dict((re.escape(k), v) for k, v in rep.items()) pattern = re.compile("|".join(rep.keys())) return pattern.sub(lambda m: rep[re.escape(m.group(0))], text) def replace_in_list( stringlist: Iterable[str], replacedict: Dict[str, str] ) -> List[str]: """ Returns a list produced by applying :func:`multiple_replace` to every string in ``stringlist``. Args: stringlist: list of source strings replacedict: dictionary mapping "original" to "replacement" strings Returns: list of final strings """ newlist = [] for fromstring in stringlist: newlist.append(multiple_replace(fromstring, replacedict)) return newlist # ============================================================================= # Mangling to ASCII # ============================================================================= def mangle_unicode_to_ascii(s: Any) -> str: """ Mangle unicode to ASCII, losing accents etc. in the process. """ # https://stackoverflow.com/questions/1207457 if s is None: return "" if not isinstance(s, str): s = str(s) return ( unicodedata.normalize("NFKD", s) .encode("ascii", "ignore") # gets rid of accents .decode("ascii") # back to a string ) # ============================================================================= # Making strings and string lists # ============================================================================= def strnum(prefix: str, num: int, suffix: str = "") -> str: """ Makes a string of the format ``<prefix><number><suffix>``. """ return f"{prefix}{num}{suffix}" def strnumlist(prefix: str, numbers: List[int], suffix: str = "") -> List[str]: """ Makes a string of the format ``<prefix><number><suffix>`` for every number in ``numbers``, and returns them as a list. """ return [f"{prefix}{num}{suffix}" for num in numbers] def strseq(prefix: str, first: int, last: int, suffix: str = "") -> List[str]: """ Makes a string of the format ``<prefix><number><suffix>`` for every number from ``first`` to ``last`` inclusive, and returns them as a list. """ return [strnum(prefix, n, suffix) for n in range(first, last + 1)] |
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