Description

FilippoPolo

opened on Dec 18, 2014

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The out keyword does not work properly when applied to an array cell. Example:

    private static void func(out double t)
    {
        t = 1.0;
    }

    public static void RunTest()
    {
        double[] d = new double[1];
        func(out d[0]);
        Console.Write(d[0]);
    }

The above code outputs 1 in C#, but it outputs 0 in SharpKit.

Activity

1. danielnachtrub commented on Aug 11, 2015

   

   danielnachtrub

   on Aug 11, 2015

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   This propably won't work on JS in general - passing arguments as ref is only supported for objects but not for primitive types.
2. danelkhen commented on Aug 11, 2015

   

   danelkhen

   on Aug 11, 2015

   Member

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   Theoretically it should work on anything, since SharpKit should wrap the object/value, and then even if the inner reference changes, the wrapper stays the same. But thanks for reporting it I'll check it out.

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