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GeezerVison is showing github.com — Algorithm-Implementations/UnsortedArray.java at master · devForTheFuture/Algorithm-Implementations Expand file tree/ Copy pathUnsortedArray.javaMore file actions 73 lines (59 loc) · 1.5 KB / Copy pathUnsortedArray.javaFile metadata and controls73 lines (59 loc) · 1.5 KB 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 package algorithms; import java.util.ArrayList; /** * Determines which number is missing from an unsorted array of values 1-100. * Iterate through the array and compute the sum of all numbers. * Now, sum of natural numbers from 1 to N, can be expressed as N(N+1)/2. In your case N=100. * Subtract the sum of the array from N(N+1)/2, where N=100. * * Complexity: O(n) * * @author joeytawadrous */ public class UnsortedArray { public static void main(String[] args) { ArrayList<Integer> list = new ArrayList<Integer>(); for(int i = 0; i < 101; i++) // leave 100 out { if(i != 77) { list.add(i); } } getMissingNumber(list); getMissingNumber2(); } /** * Prints the missing number in a list of numbers. * @param list */ public static void getMissingNumber(ArrayList<Integer> list) { int sum = 0; for (int i = 0; i < list.size(); i++) { sum += list.get(i); } // the total sum of numbers between 1 and arr.length. int total = (list.size() + 1) * list.size() / 2; System.out.println("Missing number is: " + (total - sum)); } /** * Prints the missing number in an array of numbers. */ public static void getMissingNumber2() { int[] arr = {1,2,3,5}; int indexes = 5; int values = 0; for (int i = 0; i < arr.length; i++) { indexes += i + 1; values += arr[i]; } int result = indexes - values; System.out.println("Missing number is: " + result); } } |
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