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// Alternative arrange the two given strings in one string in O(n) time complexity.

// Problem Source & Explanation: https://www.geeksforgeeks.org/alternatively-merge-two-strings-in-java/

/**

* Alternative arrange the two given strings in one string in O(n) time complexity.

* @param {String} str1 first input string

* @param {String} str2 second input string

* @returns `String` return one alternative arrange string.

const AlternativeStringArrange = (str1, str2) => {

// firstly, check that both inputs are strings.

if (typeof str1 !== 'string' || typeof str2 !== 'string') {

return 'Not string(s)'

}

// output string value.

let outStr = ''

// get first string length.

const firstStringLength = str1.length

// get second string length.

const secondStringLength = str2.length

// absolute length for operation.

const absLength =

firstStringLength > secondStringLength

? firstStringLength

: secondStringLength

// Iterate the character count until the absolute count is reached.

for (let charCount = 0; charCount < absLength; charCount++) {

// If firstStringLength is lesser than the charCount it means they are able to re-arrange.

if (charCount < firstStringLength) {

outStr += str1[charCount]

}

// If secondStringLength is lesser than the charCount it means they are able to re-arrange.

if (charCount < secondStringLength) {

outStr += str2[charCount]

}

// return the output string.

return outStr

}

export { AlternativeStringArrange }