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GeezerVison is showing github.com — Algorithm/java/coding/mergeSortedArray.java at master · lelea2/Algorithm

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//The key to solve this problem is moving element of A and B backwards. If B has some elements left after A is done, also need to handle that case.
//The takeaway message from this problem is that the loop condition. This kind of condition is also used for merging two sorted linked list.
public void merge(int A[], int m, int B[], int n) {
int i = m - 1; //m is length of array A
int j = n - 1; //n is length of array B
int k = m + n - 1;
while (k >= 0) {
if (j < 0 || (i >= 0 && A[i] > B[j])) {
A[k--] = A[i--];
} else {
A[k--] = B[j--];
}
}
}
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