#用python写一个程序，找出数组中差值为K的数共有几对 ##知乎上有人问“用python写一个程序，找出数组中差值为K的数共有几对” 如果你感觉黄哥的文章对你有帮助请打赏，支付宝账号：[email protected]
#coding:utf-8
"""
用python写一个程序，找出数组中差值为K的数共有几对
示例：
差值k=4 and 数组是[7, 6, 23,19,10,11, 9, 3, 15]
这样的结果是(7,11) (7,3) (6,10) (19,23) (15,19) (15,11) 共6对
从标准输入读入两行数据
5 2
1 5 3 4 2
第一行代表N和K, N是数组是一共有多少数字，K是所要求的差值
第二是数组，空白分格
输出到标准输出
Sample Input #00:
5 2
1 5 3 4 2
Sample Output #00:
3
Sample Input #01:
10 1
363374326 364147530 61825163 1073065718 1281246024 1399469912 428047635 491595254 879792181 1069262793
Sample Output #01:
0
"""
def diff_of_element_list(lst, k):
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"""
newlst = [i + k for i in lst]
return len(set(lst) & set(newlst))
if __name__ == '__main__':
lst = [7, 6, 23,19,10,11, 9, 3, 15]
k = 4
print(diff_of_element_list(lst, k))
lst = [1,5, 3, 4, 2]
k = 2
print(diff_of_element_list(lst, k))
n, k = input("please input n and k:\n").split()
lst = input("plesae input {0} number:\n".format(n)).split()
lst = [int(i) for i in lst]
print(diff_of_element_list(lst, int(k)))