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GeezerVison is showing javaevolved.dev — Math.clamp() | java.evolved
Date/Time
Beginner
Clamp a value between bounds with a single clear call. Code Comparison
✕ Java 8
// Clamp value between min and max
int clamped =
Math.min(Math.max(value, 0), 100);
// or: min and max order confusion
✓ Java 21+
int clamped =
Math.clamp(value, 0, 100);
// value constrained to [0, 100]
See a problem with this code? Let us know.
Why the modern way wins
📖
Self-documentingclamp(value, min, max) is unambiguous. 🛡️
Less error-proneNo more swapping min/max order by accident. 🎯
All numeric typesWorks with int, long, float, and double. Old Approach
Nested min/max
Modern Approach
Math.clamp()
Since JDK
21
Difficulty
Beginner
JDK Support
Math.clamp()
Available
Widely available since JDK 21 LTS (Sept 2023) How it works
Math.clamp(value, min, max) constrains a value to the range [min, max]. Clearer than nested Math.min/Math.max and available for int, long, float, and double. Related Documentation
Proof
Related patterns
Date/Time
Intermediate
Instant with nanosecond precisionJava 8
// Millisecond precision only
long millis =
System.currentTimeMillis();
// 1708012345678
Java 9+
// Microsecond/nanosecond precision Instant now = Instant.now(); // 2025-02-15T20:12:25.678901234Z long nanos = now.getNano();
JDK 9+
→
Date/Time
Intermediate
HexFormatJava 8
// Pad to 2 digits, uppercase
String hex = String.format(
"%02X", byteValue);
// Parse hex string
int val = Integer.parseInt(
"FF", 16);
Java 17+
var hex = HexFormat.of()
.withUpperCase();
String s = hex.toHexDigits(
byteValue);
byte[] bytes =
hex.parseHex("48656C6C6F");
JDK 17+
→
Date/Time
Beginner
Duration and PeriodPre-Java 8
// How many days between two dates?
long diff = date2.getTime()
- date1.getTime();
long days = diff
/ (1000 * 60 * 60 * 24);
// ignores DST, leap seconds
Java 8+
long days = ChronoUnit.DAYS
.between(date1, date2);
Period period = Period.between(
date1, date2);
Duration elapsed = Duration.between(
time1, time2);
JDK 8+
→
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