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#18 - 4Sum

Medium • View on LeetCode • View on GitHub

Problem Description

Given an array nums of n integers, return an array of all the unique quadruplets [nums[a], nums[b], nums[c], nums[d]] such that:

0 <= a, b, c, d < n
a, b, c, and d are distinct.
nums[a] + nums[b] + nums[c] + nums[d] == target

You may return the answer in any order.

Solution

/**
 * @param {number[]} nums
 * @param {number} target
 * @return {number[][]}
 */
var fourSum = function(nums, target) {
  const result = [];

  nums.sort((a, b) => a - b);

  for (let i = 0; i < nums.length - 3; i++) {
    for (let j = i + 1; j < nums.length - 2; j++) {
      let high = nums.length - 1;
      let low = j + 1;

      while (low < high) {
        const sum = nums[i] + nums[j] + nums[low] + nums[high];

        if (sum === target) {
          result.push([nums[i], nums[j], nums[low], nums[high]]);
          while (nums[low] === nums[low + 1]) {
            low++;
          }
          while (nums[high] === nums[high - 1]) {
            high--;
          }
          low++;
          high--;
        } else if (sum < target) {
          low++;
        } else {
          high--;
        }
      }
      while (nums[j] === nums[j + 1]) {
        j++;
      }
    }
    while (nums[i] === nums[i + 1]) {
      i++;
    }
  }

  return result;
};

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