GeezerVison

Gerrit Holl

> Currently, I would join it this way into a tab-delimeted string:
> s = string.join(l, '\t')
>
> In 1.6, I should do it this way:
> '\t'.join(s)
>
> I think it would be better to have that method on the *list*:
> s.join('\t')
>
> That's more clear, isn't it?

As Tim pointed out when they were discussed, the clearest way to express it
with the new methods is to do:

tab = '\t'

tab.join(s)

Similarly

space = ' '
space.join(s)

etc.

--david ascher